Given that PI is infinite, is it possible that all possible number combinations are available in its decimals?
Pi itself is not infinite, but the decimal expansion does go on forever, and it has been proven to be transcendental. So it is possible that all decimal combinations are in this expansion, but as far as I know, this has not been proved.
Secrets of Pi:
you can find 12345 between 666 and 888: …66612345888… consecutive at position 49704!
Occurences: Pi 1 to 100000:
numb: 0 9999
numb: 1 10138
numb: 2 9908
numb: 3 10026
numb: 4 9970
numb: 5 10027
numb: 6 10027
numb: 7 10025
numb: 8 9978
numb: 9 9902
function Occurrences(const Substring, Text: string): integer; var offset: integer; beginresult:= 0; offset:= PosEx(Substring, Text, 1); while offset <> 0 dobegininc(result); offset:= PosEx(Substring,Text, offset+length(Substring)); //writeln(itoa(offset))end;end;

Why is Pi not infinitely large, given that it has infinite digits and each one adds value? Doesn’t anything times infinity equal infinity?
Ist nicht irgendetwas mal Unendlichkeit gleich Unendlichkeit?
¿No hay nada por infinito igual a infinito?
N’est-ce pas quelque chose d’infini égal à l’infini?



My students think that since Pi is irrational, and therefore has infinite decimals, it should have every finite configuration of numbers that …
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